Cooling Load Calculator

Calculate refrigeration load in kW and Tonnes of Refrigeration (TR) for milk chilling in dairy plants.

L/hr
Volume of milk to chill per hour
°C
Temperature of incoming milk (ambient: 28–37°C)
°C
Required chilling target. Typical: 4°C for storage
%
Add 15–25% margin for system losses and peak loads
Formula
((milkFlowRate / 3600) * 1.030 * 3.9 * (inletTemp - outletTemp)) * (1 + safetyMargin / 100)
milkFlowRate Milk Flow Rate (L/hr)
inletTemp Milk Inlet Temperature (°C)
outletTemp Target Outlet Temperature (°C)
safetyMargin Safety Margin (%)
Worked Example
1
Given:
inletTemp = 35
milkFlowRate = 20000
outletTemp = 4
safetyMargin = 20
2
Apply the formula:
((milkFlowRate / 3600) * 1.030 * 3.9 * (inletTemp - outletTemp)) * (1 + safetyMargin / 100)
3
Result:829 kW829 TR

What is Cooling Load in a Dairy Plant?

Cooling load is the rate at which heat must be removed from milk (or other dairy products) to reduce its temperature from the incoming temperature to the storage/processing target temperature.

It is expressed in:

  • kW (kilowatts of heat removal)
  • TR (Tonnes of Refrigeration — 1 TR = 3.517 kW)

Correct sizing of the chilling system ensures milk reaches safe temperatures quickly, preventing bacterial growth and quality loss.

How to Use This Calculator

  1. Enter the milk flow rate (litres/hour or litres/batch)
  2. Enter the inlet temperature of incoming milk (°C)
  3. Enter the target outlet temperature (°C)
  4. The calculator gives cooling duty in kW and TR

Formula

Q (kW) = ṁ × Cp × (T_in − T_out)

Where:

  • ṁ = mass flow rate (kg/s)
  • Cp = specific heat of milk (≈ 3.9 kJ/kg·K)
  • T_in = inlet temperature (°C)
  • T_out = target outlet temperature (°C)

Refrigeration Tons (TR) = Q (kW) / 3.517

Add 15–20% safety margin for system losses and peak load variation.

Common Dairy Chilling Scenarios

ScenarioInlet TempTarget Temp
Village collection chilling30–37°C4°C
Post-pasteurization cooling72°C4°C
UHT product cooling135°C25°C (aseptic)
Cream storage10°C4°C
Butter chilling20°C8°C

Example Calculation

Chill 20,000 litres/hour of raw milk from 35°C to 4°C:

  • ṁ = 20,000 / 3600 × 1.030 = 5.72 kg/s
  • Cp = 3.9 kJ/kg·K
  • ΔT = 35 − 4 = 31°C

Q = 5.72 × 3.9 × 31 = 691 kW

TR = 691 / 3.517 = 196 TR

With 20% margin: 235 TR → select a 250 TR chiller

Refrigeration System Types in Dairy

System TypeApplicationCOP Range
Vapour compression (ammonia)Large dairy plants > 100 TR3.5–5.0
Vapour compression (Freon/HFC)< 100 TR, small plants2.5–4.0
Ice bank systemPeak demand management2.0–3.0
Glycol chillerIndirect cooling, hygiene-sensitive2.8–4.2

Energy Efficiency Tips

  1. Pre-cool with bore well water: Reduce load by 30–50% using 20–25°C groundwater
  2. Maintain condenser cleanliness: Fouled condenser raises power consumption 10–15%
  3. Optimise suction temperature: Each 1°C rise in suction = 1% energy savings
  4. Night-time chilling: Lower ambient reduces compressor head pressure
  5. Leak-free system: Refrigerant leaks reduce COP significantly